(PHP 4, PHP 5)
imagecreatefromjpeg — Create a new image from file or URL
imagecreatefromjpeg() returns an image identifier representing the image obtained from the given filename.
A URL can be used as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename and List of Supported Protocols/Wrappers for a list of supported URL protocols.
Path to the JPEG image.
Returns an image resource identifier on success, FALSE on errors.
Example #1 Example to handle an error during loading of a JPEG
<?php
function LoadJpeg($imgname)
{
/* Attempt to open */
$im = @imagecreatefromjpeg($imgname);
/* See if it failed */
if(!$im)
{
/* Create a black image */
$im = imagecreatetruecolor(150, 30);
$bgc = imagecolorallocate($im, 255, 255, 255);
$tc = imagecolorallocate($im, 0, 0, 0);
imagefilledrectangle($im, 0, 0, 150, 30, $bgc);
/* Output an error message */
imagestring($im, 1, 5, 5, 'Error loading ' . $imgname, $tc);
}
return $im;
}
header('Content-Type: image/jpeg');
$img = LoadJpeg('bogus.image');
imagejpeg($img);
imagedestroy($img);
?>
The above example will output something similar to:
Note: JPEG support is only available if PHP was compiled against GD-1.8 or later.
Windows versions of PHP prior to PHP 4.3.0 do not support access of remote files via this function, even if allow_url_fopen is enabled.