# Natural Language Toolkit: Spearman Rank Correlation # # Copyright (C) 2001-2010 NLTK Project # Author: Joel Nothman # URL: # For license information, see LICENSE.TXT """ Tools for comparing ranked lists. """ def _rank_dists(ranks1, ranks2): """Finds the difference between the values in ranks1 and ranks2 for keys present in both dicts. If the arguments are not dicts, they are converted from (key, rank) sequences. """ ranks1 = dict(ranks1) ranks2 = dict(ranks2) for k, v1 in ranks1.iteritems(): try: yield k, v1 - ranks2[k] except KeyError: pass def spearman_correlation(ranks1, ranks2): """Returns the Spearman correlation coefficient for two rankings, which should be dicts or sequences of (key, rank). The coefficient ranges from -1.0 (ranks are opposite) to 1.0 (ranks are identical), and is only calculated for keys in both rankings (for meaningful results, remove keys present in only one list before ranking).""" n = 0 res = 0 for k, d in _rank_dists(ranks1, ranks2): res += d * d n += 1 try: return 1 - (6 * float(res) / (n * (n*n - 1))) except ZeroDivisionError: # Result is undefined if only one item is ranked return 0.0 def ranks_from_sequence(seq): """Given a sequence, yields each element with an increasing rank, suitable for use as an argument to L{spearman_correlation}. """ return ((k, i) for i, k in enumerate(seq)) def ranks_from_scores(scores, rank_gap=1e-15): """Given a sequence of (key, score) tuples, yields each key with an increasing rank, tying with previous key's rank if the difference between their scores is less than rank_gap. Suitable for use as an argument to L{spearman_correlation}. """ prev_score = None rank = 0 for i, (key, score) in enumerate(scores): try: if abs(score - prev_score) > rank_gap: rank = i except TypeError: pass yield key, rank prev_score = score